单点时限: 2.0 sec

内存限制: 256 MB

You are given two vectors v1=(x1,x2,…,xn) and v2=(y1,y2,…,yn). The scalar product of these vectors is a single number, calculated as x1y1+x2y2+…+xnyn.

Suppose you are allowed to permute the coordinates of each vector as you wish. Choose two permutations such that the scalar product of your two new vectors is the smallest possible, and output that minimum scalar product.

输入格式

The first line of the input file contains integer number T - the number of test cases. For each test case, the first line contains integer number n. The next two lines contain n integers each, giving the coordinates of v1 and v2 respectively.

T = 10

100 ≤ n ≤ 800

-100000 ≤ xi, yi ≤ 100000

输出格式

For each test case, output a line

Case #X: Y

where X is the test case number, starting from 1, and Y is the minimum scalar product of all permutations of the two given vectors.

样例

input

2
3
1 3 -5
-2 4 1
5
1 2 3 4 5
1 0 1 0 1

output

Case #1: -25
Case #2: 6

#include 
#include 
#include 
using namespace std;
class SingleJob{
public:int dim;vector vecA; vector vecB;
};
int main() {int jobs, temp;SingleJob J[10];// 输入cin >> jobs;for(int i=0;i> J[i].dim;for(int j=0;j> temp;J[i].vecA.insert(J[i].vecA.end(), temp);}for(int j=0;j> temp;J[i].vecB.insert(J[i].vecB.end(), temp);}}// 输出。注意结果dotpdt是两个int型相乘，需要用longlong定义long long dotpdt=0;for(int i=0;i